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But the acceleration due to gravity is represented by the symbol g. Therefore, we can write New weight becomes 1.1 times. 0 = u – gt1 t1 = $$\frac{u}{g}$$ …(1) Weight is not a constant quantity. It is different at different places on the surface of the earth. Yes. Differences between g andG. 1. This solution contains questions, answers, images, step by step explanations of the complete Chapter 10 titled Gravitation of Science taught in class 9. [NCERT Exemplar] This will clear students doubts about any question and improve application skills while preparing for board exams. Suppose the radius of the earth becomes twice of its present radius without any change in its mass, what will happen to your weight? Question 3. ... plz answer this questions. Question 7: Law of gravitation gives the gravitational force between (a) the earth and a point mass only Gravitational constant is numerically equal to the force of attraction between two masses of 1 kg that are separated by a distance of 1 m. State the universal law of gravitation. Given m1 = 3 kg; m2 = 12 kg Question 1. At the poles. One second later, he throws another stone. If the mass of a body is 9.8 kg on the earth, what would be its mass on the moon? The time taken for a body is less if the acceleration due to gravity is more when the initial velocities and the distance travelled are the same. QUESTION 6 (2002 EXAM) (a) Calculate the magnitude of the gravitational acceleration g at the Earth's surface, using Newton's second law and the law of universal gravitation. Practicing All Gravitation - IIT JEE Entrance Exam Questions and Answers in online helps you to improve your ability to attend the real time maths, chemistry, physics Entrance Exams. Upward motion The acceleration due to gravity does not depend upon the mass of the stone or body. The standard kilogram is the mass of a block of a platinum alloy kept at the international bureau of weights and measures near Paris in France. ∴ 49 = 0 × t + $$\frac{1}{2}$$ × 9.8 × t2 Answer: The ‘G’ is a universal constant, i.e., its value is the same (i.e. Draw areal velocity versus time graph for mars. When body is at a distance V from centre of the earth then g = $$\frac{G M}{r^{2}}$$. This hypothesis is not correct. Give reasons. Which stone would reach the ground first and why? Both C and D; [(Kg-m/Sec 2) = N] Q.19 Weight of free fall object is. Question 17. Isaac Newton. Its value also varies from one celestial body to another. Mention any four phenomena that the universal law of gravitation was able to explain. Here, s = 100 m, u = 0 If the average distance between the Sun and the Earth is 1.5 x 10 11 m, calculate the force exerted by the Sun on the Earth and also by Earth on the Sun. It will remain the same on the moon, i.e., 9.8 kg. If the radius of the earth becomes twice of its original radius, then Weight is the force of gravity acting on the body. Give one example each of central force and non-central force. (g) At which point does the bal 1 have the same speed as when it was thrown? On the moon’s surface, the acceleration due to gravity is 1.67 ms-2. According to Newton’s third law of motion, action and reaction are equal and opposite. Previous: Contents: Next: Question 4. radius of the earth, Re = 6400 km Answered by Expert ICSE IX Physics Upthrust in Fluids, Archimedes' Principle and Floatation. Using physics, you can calculate the gravitational force that is exerted on one object by another object. The weight of the body on the moon is about one-sixth of its weight on the earth. Question 1. Question 8. Answer: Now, mass of the earth, Me = 6 × 1024 kg Weight of a body ∝ $$\frac{M}{R^{2}}$$ Question 4. “Every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.” Let us consider two bodies A and B of masses m1 and m2 which are separated by a distance r. Then the force of gravitation (F) acting on the two bodies is given by These Gravitation Objective Questions with Answers are important for competitive exams like JEE, NEET, AIIMS, JIPMER etc. Answer: Define acceleration due to gravity. (ii) Weight = $$\frac{G M m}{r^{2}}$$, where r is the radius of the earth. Page No: 134. In a hypothetical case, if the diameter of the earth becomes half of its present value and its mass becomes four times of its present value, then how would the weight of any object on the surface of the earth be affected? Question 15. Let the mass, m3 = 0.5 kg be placed at a distance of ‘x’ m from m1, as shown in figure. Prove that if the earth attracts two bodies placed at same distance from the centre of the earth with the same force, then their masses are equal. [NCERT Exemplar] MCQs on CBSE Class 9 Science Chapter- Gravitation are provided here with answers. Zero. It means that the force on the apple due to earth’s attraction is equal to that on the earth due to apple’s attraction. Question 1. The acceleration produced in the motion of a body falling under the force of gravity is called acceleration due to gravity. Height of the building, h = ? Let P and Q be the two bodies, Answer: This law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of distance between them. At the equator. Mass of the earth, Me = 6 × 1024 kg The earth is acted upon by gravitation of sun, even though it does not fall into the sun. Answer: 1. Question 2. Answer: According to Newton’s third law of … Answer: Show that the weight of an object on the moon is $$\frac{1}{6}$$ th of its weight on the earth. (ii) As v = u2 + 2 gs = $$20 \sqrt{2}$$ms-1, Question 6. The Following Section consists of Gravitation Questions on Physics. (Where Ve is the volume of the earth) Since, the two forces, i.e., Fp and FQ are equal, thus from (1) and (2), When r changes to 2r, the new weight is given by What does a small value of G indicate? Where, R is the distance of the body from the centre of the earth. Then force acting on m3 due to m1, is equal and opposite to the force acting on m3 due to m2. New mass, M’=M + 10% of M Answer: Answer: (a) No Derive expression for force of attraction between two bodies and then define gravitational constant. Two bodies of masses 3 kg and 12 kg are placed at a distance 12 m. A third body of mass 0.5 kg is to be placed at such a point that the force acting on this body is zero. Velocity-time graph for the ball’s motion is shown in figure. Answer: Answer: Here are some practice questions that you can try. And Radius of the earth, Re = 6.4 × 106 m. Question 7. (b) No. Initial speed, u = 0.5 m/s Thus, the gravitational constant G is numerically equal to the force of gravitation which exists between two bodies of unit masses kept at a unit distance from each other. Suppose the mass of the moon is Mm and its radius is Rm. Question 3. Question 7. As per the universal law of gravitation, the force of attraction between the earth and the body P is given by, Answer: ∴ v = 0 + (-10) × 2 = -20 ms-1 A stone dropped from the roof of a building takes 4s to reach the ground. G = F If it does, why does the earth not move towards the apple? Answer. If you are a student of class 9 who is using NCERT Textbook to study Science, then you must come across Chapter 10 Gravitation. Answer: Both the bodies fall with the same acceleration towards the surface of the earth. Define the standard kilogram. Answer: Justify your answer. What keeps the moon in uniform circular motion around the earth? Answer: If it does, why does the earth not move towards the apple? But we know, acceleration ∝ 1/m. Answer: Answer: The position of required point is at a distance of 4 m from mass of 3 kg. We know that g = $$\frac{G M}{R^{2}}$$ or M = $$\frac{g R^{2}}{G}$$ Answer The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force.The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Answer: Acceleration in downward direction = g Zero. Do fluids possess weight? 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Do you agree with his hypothesis or not? The two bricks like a single body, fall with the same speed to reach the ground at the same time in case of free fall. Two planets of radii R 1 and R 2 have the same density. Take g = 9.8 m/s2. ans F ∝ $$\frac{1}{r^{2}}$$ ..(2) What will happen to the gravitational force between two bodies if the masses of one body is doubled? No. Question 1. The universal law of gravitation was able to explain successfully. 3. W = $$\frac{G M m}{(2 r)^{2}}$$ Weight of an object is directly proportional to the mass of the earth and inversely proportional to the square of the radius of the earth, i.e., or t = $$\frac{0.5}{9.8}$$ = 0.05 s. Question 11. Question 4. Numericals It is the measure of inertia of the body. Yes. Question 13. Why does formation of tides takes place in sea or ocean? Both stones will take the same time to reach the ground because the two stones fall from the same height. ⇒ Average density of the earth, D = $$\frac{\text { Mass }}{\text { Volume }}=\frac{g R^{2}}{G \times V e}$$ or, v = $$\sqrt{800}$$ Does the apple also attract the earth? So, acceleration = $$\frac{\text { Force }}{\text { Mass }}=\frac{20}{1}$$ = 20 m/s2, Question 3. For the second stone, (i) How high will it go before it begins to fall? F ∝ $$\frac{m_{1} \times m_{2}}{r^{2}}$$ % Variation in the weight of a body = % Change in g = 0.7%. Answer: Answer: (d) The quantity G is universal constant of nature. A stone is dropped from the top of a 40 m high tower. Answer: Then weight becomes Wn = mG $$\frac{4 M}{\left(\frac{R}{2}\right)^{2}}$$ = (16 m G) $$\frac{M}{R^{2}}$$ = 16 × W0 On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Dividing equation (1) by (2), we get Find out the speed with which he threw the second stone. A: mass of the object × gravitational acceleration B: Zero Answer: Question 2. The ratio of their accelerations due to gravity at the surface is (R 1 /R 2) 2 (R 2 /R 1) 2 ... Click the "Score and Show Answer(s)" button for explanations. mass of the moon, Mm = 7.4 × 1022 kg Therefore, the body appears to be floating weightlessly. What would happen to your weight? Answer: Access Answers to NCERT Class 9 Science Chapter 10 – Gravitation ( All In text and Exercise Questions Solved) Exercise-10.1 Page: 134. The accepted value of G is 6.67x 1CT-11 Nm 2 kg-2. Answer: […] The way the world works is exciting. Acceleration due to gravity is the acceleration acquired by a body due to the earth’s gravitational pull on it. [NCERT Exemplar] where Me = mass of earth and Re = radius of earth. Answer: Fill in the blanks : _____ of an object is the force of gravity acting on it.. Class 9 - Physics - Gravitation . Question 5. or, v2 – 02 = 2(-10) × (-40) In case of free fall acceleration does not depend upon mass and size. TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. Gravity itself is a natural phenomenon. h2 = $$\frac{1}{2} g t_{2}^{2}$$, [NCERT Exemplar] Question 14. The moon will begin to move in a straight line in the direction in which it was moving at that instant because the circular motion of moon is due to centripetal force provided by the gravitational force of the earth. v = u + gt1 $$\frac{W_{m}}{W_{e}}=\frac{M_{m}}{M_{e}} \times \frac{R_{e}^{2}}{R_{m}^{2}}$$ …. How is gravitation different from gravity? How does the force of attraction between the two bodies depend upon their masses and distance between them? A student thought that two bricks tied together would fall faster than a single one under the action of gravity. How much do you know about gravitation? (a) In which direction is the ball moving at point C? When a body is thrown vertically upwards, what is its final velocity? Answer: Question 19. Answer: = M + $$\frac{10}{100}$$M = M + $$\frac{M}{10}$$ = $$\frac{11M}{10}$$ = 1.1 M Thus, the packets will remain in air for longer time interval, when it is dropped at the equator. From (1) and (2), we get t1 = t2 Why is ‘G’ called the universal gravitational constant? Is the time taken by a body to rise to the highest point equal to the time taken to fall from the same height? Answer: Wm = $$\frac{G M_{m} m}{R_{m}^{2}}$$ …(1) ⇒ t = $$\sqrt{10}$$ = 3.16 s The constant ‘G’ is universal because it is independent of the nature and sizes of bodies, the space where they are kept and at the time at which the force is considered. , Difficult word of chapter the tale of melon city. So, when dropped from the same height a body reaches the ground quicker at the poles than at the equator. Question Answers, Page 134. [NCERT Exemplar] FQ = $$\frac{G \times M_{e} \times m_{2}}{R^{2}}$$ ……. Answer: Answer: Give three differences between acceleration due to gravity (g) and universal gravitational constant (G). Two objects of masses ml and m2 having the same size are dropped simultaneously from heights h1 and h2, respectively. Calculate the value of acceleration due to gravity g using the relation between g and G. Free Question Bank for NEET Physics Gravitation. As u = 0, h1 = $$\frac{1}{2} g t_{1}^{2}$$ For both the stones Therefore, the packets fall slowly at equator in comparison to the poles. v2 = 2gs = 2 × 9.8 × 100 = 1960 Thus, equation (3) becomes, If a body of mass m is placed on the surface of moon, then weight of the body on the moon is Question 9. The solved question papers from chapter 08 Gravitation have all type of questions may be asked in annual exams such as VSA very short answer type questions, SA short answer type questions, LA long answer type questions, VBA value based questions and HOTS higher order thinking skill based questions. The mass of the Sun is 2 x 10 30 kg and that of the Earth is 6 x 10 24 kg. If a satellite of mass m is revolving around the earth with distance rfrom centre, then total energy is Answer: (c) The satellite revolving around the earth has two types of energies. ∴ v = u Answer: Register online for Science tuition on Vedantu.com to score more marks in your examination. (d) Acceleration = 10 ms-2 The force (F) of gravitational attraction on a body of mass m due to earth of mass M and radius R is given by 3. Class 9 | Science | Chapter 10 |Gravitation| NCERT Solutions. Question 11. NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12, Extra Questions for Class 9 Science Chapter 10 Gravitation. Answer: Answer: Suppose the mass of the earth somehow increases by 10% without any change in its size. The entire NCERT textbook questions have been solved by best teachers for you. That is, for the second stone, t = (3.16 – 1)s = 2.16s A ball is thrown up with a speed of 0.5 m/s. (c) At which point is the bal 1 at its maximum height? Question 5. Why can one jump higher on the surface of the moon than on the earth? Question 1. Calculate the average density of the earth in terms of g, G and R. Answer: Answer: Find the position of that point. The huge collection of Questions and Answers for academic studies, CBSE school. (f) What is the bal l’s acceleration at point B? Comment. u = 0 + gt2 Our online gravitation trivia quizzes can be adapted to suit your requirements for taking some of the top gravitation quizzes. Original weight, W0 = mg = mG $$\frac{M}{R^{2}}$$ A force of 20 N acts upon a body whose weight is 9.8 N. What is the mass of the body and how much is its acceleration? v = $$\sqrt{1960}$$m/s = 44.2 m/s. Question 2. Q.18 What is the weight of a body of mass 1 kg? 1. Why does a body orbiting in space possess zero weight with respect to a spaceship? Question 6. State the universal law of gravitation. Here, initial velocity, u = 0 or – 0.25 = -19.6 h Question 1. Q1. The earth attracts an apple. Question 1. Practice questions The gravitational force between […] Here, if the masses mx and m2 of the two bodies are of 1 kg and the distance (r) between them is 1 m, then putting m1 = 1 kg, m2 = 1 kg and r = 1 m in the above formula, we get (i) Original weight = $$\frac{G M m}{r^{2}}$$, where M is the mass of the earth. Question 4. Gravitational force. (b) At which point is the bal 1 stationary? Fp = $$\frac{G \times M_{e} \times m_{1}}{R^{2}}$$ …..(1) Gravitation is the force of attraction that tends to draw together any two objects in the universe. (i) We know v2 – u2 Question 9. Question 21. It occurs only when a body is in a state of free fall under the effect of gravity alone. F ∝ m1 × m2…(1) Gravitation Multiple Choice Questions & Answers for competitive exams. Final speed, v = 0 (G = 6.67 × 1011 Nm2kg-2) Answer: Asked by Umesh 1st December 2017 9:49 AM . Question 2. $$\frac{G \times M e \times m_{1}}{R^{2}}=\frac{G \times M_{e} \times m_{2}}{R^{2}}$$ Its SI unit is the same as the SI unit of force, i.e., Newton (N). 6.7 × 10-11 Nm2 kg-2) everywhere in the universe. The value of ‘g’ at the equator of the earth is lesser than that at poles. ∴ F = ma Answer: They both hit the ground at the same time. Question 12. Professionals, Teachers, Students and Kids Trivia Quizzes to test your knowledge on the subject. The entire NCERT textbook questions have been solved by best teachers for you. Answer According to question, M S = Mass of the Sun = 2×10 30 kg M E = Mass of the Earth = 6×10 24 kg R = Average distance between the Earth and the Sun = 1.5×10 11 m From Universal law of gravitation, If the small and big stones are dropped from the roof of a house simultaneously, they will reach the ground at the same time. F ∝ m,1m2 and F ∝ $$\frac{1}{r^{2}}$$ Take the Quiz and improve your overall Physics. This test will determine your knowledge of the subject. Ratio will not change in either case because acceleration remains the same. As the body falls back to the earth with the same velocity it was thrown vertically upwards. Answer: Answer: ∴ For the second stone, Very Short Answer Type Questions. Yes. This force depends on the product of the masses of the planet and sun and the distance between them. ⇒ Time of ascent = Time of descent. Browse from thousands of Gravitation questions and answers (Q&A). or F = G × $$\frac{m_{1} m_{2}}{r^{2}}$$ ……..(3) Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. and radius of the moon, Rm = 1740 km (e) What is the ball’s acceleration at point A? F = $$G \frac{m M}{R^{2}}$$ …..(1) Question 20. t2 = u/g …(2) Question 16. (f) Acceleration = 10 ms-2 where G is a constant known as universal gravitational constant. From a cliff of 49 m high, a man drops a stone. Change in the atmosphere are attracted by gravitational force between moon and the distance between?! Equator to the time of fall of the planet and sun and the distance between them try... Sun and the earth is lesser than that at poles apple falling a. Becomes zero, then which direction will the moon will remain in air in the body to. 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About any question and improve application skills while preparing for board exams one jump higher on the is... Size are dropped simultaneously from heights h1 and h2, respectively why all of gravitation D ; [ ( 2... Causes gravity, what is its initial velocity some of the top of a body is 9.8 kg is. Universal gravitational constant rise to the time taken by a body is dropped from the same ( i.e 24! At point B with which he threw the second stone was thrown downward with a of. Also find the percentage change in its mass fall of the earth, what gravity! Trivia quizzes to test your knowledge on the earth somehow increases by 10 % without any change in mass. And h2, respectively ) and universal gravitational constant ( g ) and universal gravitational constant ( g and. Place on the earth for board exams tends to draw together any two bodies then!, teachers, students and Kids Trivia quizzes to test your knowledge with gravitation quiz questions Who formulated universal. 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To a spaceship = % change in the atmosphere are attracted by gravitational force of between... 1.67 ms-2 test your knowledge on the product of the earth is than! Force that a planet gravitation questions and answers to revolve around the earth here are some practice questions that you try! Online gravitation Trivia quizzes can be adapted to suit your requirements for taking some of the moon of proportionality Newton. Subject experts and students has answered all of gravitation quizzes How gravity,... Planet and sun and the earth becomes twice of its original radius any! ( ii ) How high will it take to reach the ground which stone would reach the ground us... Upon the mass of the earth does not depend upon mass and size stone is dropped the... Move if No other celestial body to rise to the time taken by a body is doubled force! Revolve around the earth somehow increases by 10 % without any change in =... 9.8 Kg-m/Sec 2 D: 9.8 N. answer: zero gravitation Class 9 - -. 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